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3b^2-11b-21=0
a = 3; b = -11; c = -21;
Δ = b2-4ac
Δ = -112-4·3·(-21)
Δ = 373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{373}}{2*3}=\frac{11-\sqrt{373}}{6} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{373}}{2*3}=\frac{11+\sqrt{373}}{6} $
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